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-x^2+35x+16=0
We add all the numbers together, and all the variables
-1x^2+35x+16=0
a = -1; b = 35; c = +16;
Δ = b2-4ac
Δ = 352-4·(-1)·16
Δ = 1289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-\sqrt{1289}}{2*-1}=\frac{-35-\sqrt{1289}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+\sqrt{1289}}{2*-1}=\frac{-35+\sqrt{1289}}{-2} $
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